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Question

20cis(19π18)5cis(2π9)=

A
23+2i
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B
232i
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C
23+2i
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D
2+2i3
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E
22i3
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Solution

The correct option is A 23+2i
20ei19π185ei2π/9
4ei[(19π/18)(2π/9)]
4ei[(15×180)/18]
4ei×150
23+2i

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