The correct option is B 14 4×12 = 48 (2448)^2 = (12)^2 #160; = 14 Hence, Option B is correct. ...

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Standard VIII

Mathematics

Comparison of Quantities Using Exponents

244× 122 = ?

Question

$(\frac{24}{4 \times 12})^{2}$ = ?

\frac{3}{4}

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\frac{1}{4}

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\frac{5}{4}

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\frac{1}{3}

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Solution

The correct option is B $\frac{1}{4}$
$4 \times 12$ $=$ $48$
$(\frac{24}{48})^{2}$ = $(\frac{1}{2})^{2}$
$=$ $\frac{1}{4}$
Hence, Option B is correct.

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Similar questions

Find the mode from the given data.

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Q. Observe the following pattern

1 = \frac{1}{2} \{1 \times (1 + 1)\} 1 + 2 = \frac{1}{2} \{2 \times (2 + 1)\} 1 + 2 + 3 = \frac{1}{2} \{3 \times (3 + 1)\} 1 + 2 + 3 + 4 = \frac{1}{2} \{4 \times (4 + 1)\}

and find the values of each of the following:
(i) 1 + 2 + 3 + 4 + 5 + ... + 50
(ii) 31 + 32 + ... + 50

$(i) 1 \div \frac{1}{3} (i i) 3 \div \frac{3}{5} (i i i) - \frac{5}{12} \div \frac{1}{16} (i v) - \frac{21}{16} \div (\frac{- 7}{8}) (v) 0 \div (- \frac{4}{7}) (v i) \frac{8}{- 5} \div \frac{24}{25} (v i i) - \frac{3}{4} \div (- 9) (v i i i) ‘ \frac{3}{4} \div (- \frac{5}{12}) (i x) - 5 \div (- \frac{10}{11}) (x) \frac{- 7}{11} \div (\frac{- 3}{44})$

Q. Find the principal value of each of the following:

(i)

\sin^{- 1} (- \frac{\sqrt{3}}{2})

(ii)

\sin^{- 1} (\cos \frac{2 π}{3})

(iii)

\sin^{- 1} (\frac{\sqrt{3} - 1}{2 \sqrt{2}})

(iv)

\sin^{- 1} (\frac{\sqrt{3} + 1}{2 \sqrt{2}})

(v)

\sin^{- 1} (\cos \frac{3 π}{4})

(vi)

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Gopi spun the spinner 30 times and got the following results:

2, 1, 4, 2, 4, 5, 1, 4, 1, 5, 3, 1, 4, 2, 3, 1, 5, 4, 4, 2, 3, 3, 5, 4, 2, 2, 5, 3, 1, 4

What is the frequency of 4?

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(244×12)2 = ?

The correct option is B 144×12 = 48(2448)2=(12)2 = 14Hence, Option B is correct.

$(\frac{24}{4 \times 12})^{2}$ = ?

The correct option is B $\frac{1}{4}$
$4 \times 12$ $=$ $48$
$(\frac{24}{48})^{2}$ = $(\frac{1}{2})^{2}$
$=$ $\frac{1}{4}$
Hence, Option B is correct.