The correct option is C x=2 2x 3 2 x+1 3 = 3x 8 4 = gt;(6x 9 2x 2)× 4=(3x 8)× 6 = gt;16x 44=18x 48 = gt;2x=4 = gt ...

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Standard VIII

Mathematics

Reducing Equations to Simpler Form

2x-32-x+13=3x...

Question

$\frac{2 x - 3}{2} - \frac{(x + 1)}{3} = \frac{3 x - 8}{4}$

x = 4

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x = - 2

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x = 2

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x = - 4

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Solution

The correct option is C $x = 2$
$\frac{2 x - 3}{2} - \frac{x + 1}{3} = \frac{3 x - 8}{4} => (6 x - 9 - 2 x - 2) \times 4 = (3 x - 8) \times 6 => 16 x - 44 = 18 x - 48 => 2 x = 4 => x = 2$

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Similar questions

2x-3/2 - x+1/3 = 3x-8/4

Solve :

$(i) \frac{1}{3} x - 6 = \frac{5}{2} (i i) \frac{2 x}{3} - \frac{3 x}{8} = \frac{7}{12} (i i i) (x + 2) (x + 3) + (x - 3) (x - 2) - 2 x (x + 1) = 0 (i v) \frac{1}{10} - \frac{7}{x} = 35 (v) 13 (x - 4) - 3 (x - 9) - 4 (x + 4) = 0 (v i) x + 7 - \frac{8 x}{3} = \frac{17 x}{6} - \frac{5 x}{8} (v i i) \frac{3 x - 2}{4} - \frac{2 x + 3}{3} = \frac{2}{3} - x (v i i i) \frac{x + 2}{6} - (\frac{11 - x}{3} - \frac{1}{4}) = \frac{3 x - 4}{12} (i x) \frac{2}{5 x} - \frac{5}{3 x} = \frac{1}{15} (x) \frac{x + 2}{3} - \frac{x + 1}{5} = \frac{x - 3}{4} - 1 (x i) \frac{3 x - 2}{3} + \frac{2 x + 3}{2} = x + \frac{7}{6} (x i i) x - \frac{x - 1}{2} = 1 - \frac{x - 2}{3} (x i i i) \frac{9 x + 7}{2} - (x - \frac{x - 2}{7}) = 36 (x i v) \frac{6 x + 1}{2} + 1 = \frac{7 x - 3}{3}$

Q. Solve:

\frac{2 x - 3}{2} - \frac{x + 1}{3} = \frac{3 x - 8}{4}

Statement 1: The value of the polynomial ${x}^{5}+ 2{x}^{4}+ 3{x}^{3}+ {x}^{2}– 7x + 8$ at x = -1 is 14.

Statement 2: The polynomial ${x}^{5}+ 2{x}^{4}+ 3{x}^{3}+ {x}^{2}– 7x + 8$ when divided by x + 1, gives 14 as remainder.

Q. Let

p (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 3 & 3 x & 3 x^{2} + 2 3 x & 3 x^{2} + 2 & 3 x^{3} + 6 x 3 x^{2} + 2 & 3 x^{3} + 6 x & 3 x^{4} + 12 x^{2} + 2 \end{matrix} ∣ ∣ ∣ ∣ ∣

q (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 2 & 2 & 2 2 + x & 3 + x & 4 + x (2 + x)^{2} & (3 + x)^{2} & (4 + x)^{2} \end{matrix} ∣ ∣ ∣ ∣ ∣

r (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} cos (x + π / 4) & sin (x + π / 4) & 1 cos (x + π / 2) & sin (x + π / 2) & \sqrt{2} cos (x + 3 π / 4) & sin (x + 3 π / 4) & 1 \end{matrix} ∣ ∣ ∣ ∣ ∣

s (x) = ∣ ∣ ∣ ∣ ∣ \begin{matrix} 1 & 2 x & 2 x + 1 4 x & 2 x (2 x - 1) & 2 x (2 x + 1) 6 x (2 x - 1) & 4 x (2 x - 1) (x - 1) & 2 x (4 x^{2} - 1) \end{matrix} ∣ ∣ ∣ ∣ ∣

Match the expressions on the left with their properties or values on the right.

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2x−32−(x+1)3=3x−84

The correct option is C x=22x−32−x+13=3x−84=>(6x−9−2x−2)×4=(3x−8)×6=>16x−44=18x−48=>2x=4=>x=2

$\frac{2 x - 3}{2} - \frac{(x + 1)}{3} = \frac{3 x - 8}{4}$

The correct option is C $x = 2$
$\frac{2 x - 3}{2} - \frac{x + 1}{3} = \frac{3 x - 8}{4} => (6 x - 9 - 2 x - 2) \times 4 = (3 x - 8) \times 6 => 16 x - 44 = 18 x - 48 => 2 x = 4 => x = 2$