Question

$(-\frac{3}{4}{)}^{11}÷[(-\frac{3}{4}{)}^3\times (-{\frac{3}{4}}^6\left)\right]$

Answer 1

$={(-\frac{3}{4})}^{11}÷[{(-\frac{3}{4})}^3\times {(-\frac{3}{4})}^6]$

$={(-\frac{3}{4})}^{11}÷{(-\frac{3}{4})}^{3+6}$

$={(-\frac{3}{4})}^{11}÷{(-\frac{3}{4})}^9$

$={(-\frac{3}{4})}^{11-9}={(-\frac{3}{4})}^2$

$=\frac{(-3)\times (-3)}{4\times 4}=\frac{9}{16}$.