Question

Evaluate: $\frac{3t-2}{4}-\frac{2t+3}{3}=\frac{2}{3}-t$

Answer 1

We have

$\frac{3t-2}{4}-\frac{2t+3}{3}=\frac{2}{3}-t$

$\Rightarrow \frac{3(3t-2)-4(2t+3)}{12}=\frac{2-3t}{3}$

$\Rightarrow 9t-6-8t-12=\frac{2-3t}{3}\times 12$

$\Rightarrow t-18=8-12t$

$\Rightarrow 13t=26$

$\therefore t=\frac{26}{13}=2$