$\frac{4}{25}$ coulomb of charge contains ______ electrons.

10^{15}

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10^{18}

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10^{20}

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none of these

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Solution

The correct option is C $10^{18}$
If n be the number of electrons contain in charge q, then $q = n e$
Thus, $n = \frac{q}{e} = \frac{4 / 25}{1.6 \times 10^{- 19}} = 10^{18}$

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Similar questions

One coulomb charge is equivalent to the charge contained in:
(a) $2.6 \times 10^{19}$ electrons
(b) $6.2 \times 10^{19}$ electrons
(c) $2.65 \times 10^{18}$ electrons
(d) $6.25 \times 10^{18}$ electrons

\frac{4}{25}

Coulomb of charge contains .................. electrons:

Q. Calculate the charge of

6.24 \times 10^{18}

electrons (in coulomb).

Q. At a certain time, a radioactive sample contains

2 \times 10^{20} atoms

and its disintegration rate is

3 \times 10^{10} atoms/sec

. When

2 \times 10^{15}

atoms are left to decay, its disintegration rate will be (

atoms/sec)

Q. The value of charge on the oil droplets experimentally observed were

- 1.6 \times 10^{- 19}

and

- 4 \times 10^{- 19}

coulomb. The value of the electronic charge, indicated by these results is:

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425 coulomb of charge contains ______ electrons.

The correct option is C 1018If n be the number of electrons contain in charge q, then q=neThus, n=qe=4/251.6×10−19=1018

$\frac{4}{25}$ coulomb of charge contains ______ electrons.

The correct option is C $10^{18}$
If n be the number of electrons contain in charge q, then $q = n e$
Thus, $n = \frac{q}{e} = \frac{4 / 25}{1.6 \times 10^{- 19}} = 10^{18}$