494x-232x-1-x3-192x-8-

Solve : 49(4x) 23(2x) 1+x3=19(2x+8) We are given, 49(4x) 23(2x) 1+x3 = 19(2x+8) let multiply whole equation by g. we get, ∴ 9[49(4x) 23(2x) 1+x3] = ...

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Standard X

Mathematics

Solving Simultaneous Linear Equation Using Cramer's Rule

494x-232x-1+x...

Question

$\frac{4}{9} (4 x) - \frac{2}{3} (2 x) - \frac{1 + x}{3} = \frac{1}{9} (2 x + 8)$ .

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Solution

Solve : $\frac{4}{9} (4 x) - \frac{2}{3} (2 x) - \frac{1 + x}{3} = \frac{1}{9} (2 x + 8)$
We are given,
$\frac{4}{9} (4 x) - \frac{2}{3} (2 x) - \frac{1 + x}{3} = \frac{1}{9} (2 x + 8)$
let multiply whole equation by g. we get,
$∴ 9 [\frac{4}{9} (4 x) - \frac{2}{3} (2 x) - \frac{1 + x}{3}] = 9 [\frac{1}{9} (2 x + 8)]$
$4 (4 x) - 6 (2 x) - 3 (1 + x) = (2 x + 8)$
$16 x - 12 x - 3 - 3 x = 2 x + 8$
$2 x - x = - 3 - 8$
$x = - 11$

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49(4x)−23(2x)−1+x3=19(2x+8).

Solve : 49(4x)−23(2x)−1+x3=19(2x+8)We are given,49(4x)−23(2x)−1+x3=19(2x+8)let multiply whole equation by g. we get,∴9[49(4x)−23(2x)−1+x3]=9[19(2x+8)]4(4x)−6(2x)−3(1+x)=(2x+8)16x−12x−3−3x=2x+82x−x=−3−8x=−11

$\frac{4}{9} (4 x) - \frac{2}{3} (2 x) - \frac{1 + x}{3} = \frac{1}{9} (2 x + 8)$ .