Question

$\frac{5}{8}$ times the original number of participants of a chess tournament leave the tournament. If there were $16$ chess players at the beginning of the tournament, how many are still there?

• A. $2$
• B. $6$
• C. $7$
• D. $4$

Answer 1

The correct option is B $6$

Total number of players at the beginning of the tournament $=16$
Number of players that leave the tournament $=\frac{5}{8}\times 16=\frac{5\times 16}{8}=\frac{80}{8}=10$
$\text{Number of players still there = total number of players - number of players that leave the tournament}=16–10=6$
Hence, $6$ players are still there.