Question

$\frac{72}{7}÷2\frac{18}{21}=$ $3\frac{x}{5}$. Find x.

Answer 1

Forthe value of $x$, we have to solve the given equation:-

$\Rightarrow \frac{72}{7}÷2\frac{18}{21}=3\frac{x}{5}$

$\Rightarrow \frac{72}{7}÷\frac{42+18}{21}=\frac{15+x}{5}$

$\Rightarrow \frac{72}{7}÷\frac{60}{21}=\frac{15+x}{5}$

$\Rightarrow \frac{72}{7}\times \frac{21}{60}=\frac{15+x}{5}$

$\Rightarrow \frac{18}{5}=\frac{15+x}{5}$ {cancle$5$ both sides}

$\Rightarrow 18=15+x$

$\Rightarrow x=18-15$

$\therefore x=3$