The correct option is C 25 (8^ 1· #10;5^3/2^ 4· 625) = (2^4· 5^3/8· 5^4) = (16/8· #10;5) =(2/5) ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Laws of Exponents for Real Numbers

8-1× 532-4× 6...

Question

$\frac{8^{- 1} \times 5^{3}}{2^{- 4} \times 625} =$

\frac{5}{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{2}{5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

25

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{2}{5}$
$(\frac{8^{- 1} \cdot 5^{3}}{2^{- 4} \cdot 625}) = (\frac{2^{4} \cdot 5^{3}}{8 \cdot 5^{4}}) = (\frac{16}{8 \cdot 5}) = (\frac{2}{5})$

Suggest Corrections

Similar questions

\frac{11}{12} \div (\frac{5}{9} \times \frac{18}{25})

(2 \frac{1}{2} \times \frac{8}{10}) \div (1 \frac{1}{2} + \frac{5}{8})

\frac{15}{16}

(\frac{5}{6} - \frac{1}{2}) \div \frac{10}{11}

\frac{9}{8} \div \frac{3}{5}

(\frac{3}{4} + \frac{3}{5})

\frac{2}{5} \div {\frac{1}{5} o f [\frac{3}{4} - \frac{1}{2}] - 1}

(1 \frac{3}{4} \times 3 \frac{1}{7}) - (4 \frac{3}{8} \div 5 \frac{3}{5})

\frac{8^{- 1} \times 5^{3}}{2^{- 4}}

(5^{- 1} \times 2^{- 1}) \times 6^{- 1}

5^{k^{2}} (25^{2 k}) (625) = 25 \sqrt{5}

k < - 1

k

a^{4} - 625

(a^{2} + 25) (a + 5) (a - 5)

{[{(3^{5 / 2} \times 5^{3 / 4}) \div 2^{- 5 / 4}} \div {16 \div (5^{2} \times 2^{1 / 4} \times 3^{1 / 2})}]}^{1 / 5}

Join BYJU'S Learning Program