9-8-94sin-113-94sin -12-23

9π #160; / 8 9 / 4 sin ^ 1 1 / 3 = 9 / 4 sin ^ 1 2√( 2 ) #160; / 3 3.534 0.739=2.795 #160; 2.795=2.795 ...

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Derivative of Standard Functions

9π8-94sin-113...

Question

$\frac{9 π}{8} - \frac{9}{4} {sin}^{- 1} \frac{1}{3} = \frac{9}{4} {sin}^{- 1} \frac{2 \sqrt{2}}{3}$

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\frac{9 π}{8} - \frac{9}{4} {sin}^{- 1} \frac{1}{3} = \frac{9}{4} {sin}^{- 1} \frac{2 \sqrt{2}}{3}

Prove that $\frac{9 π}{8} - \frac{9}{4} s i n^{- 1} (\frac{1}{3}) = \frac{9}{4} s i n^{- 1} (\frac{2 \sqrt{2}}{3})$

\frac{9 π}{8} - \frac{9}{4} {sin}^{- 1} (\frac{1}{3}) = \frac{9}{4} {sin}^{- 1} (\frac{2 \sqrt{2}}{3})

\frac{9 π}{8} - \frac{9}{4} {sin}^{- 1} (\frac{1}{3}) = \frac{9}{4} {sin}^{- 1} (\frac{2 \sqrt{2}}{3})

2 s i n^{- 1} x + 3 s i n^{- 1} y + 4 s i n^{- 1} z = \frac{9 π}{2}

\frac{1}{2 x} + \frac{1}{3 y} + \frac{1}{4 z}

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