(am)×(an)(ap) can be rewritten as:
am−p−n
am+n−p
an−p−m
ap−m+n
We know that for any integer: m, n and a, (a≠0),am×an=am+naman=am−nSo, (am)× (an)(ap)=am+nap=am+n−p
Is am×an=am+n
aman=am−n, m>n