Cos 90 o - cos-tan- -cos 2 90 o - -1

cos(90^o θ)cosθtanθ+cos^2(90^o θ)=1 L.H.S =cos(90^o θ)cosθtanθ+cos^2(90^o θ) =sinθcosθsinθcosθ+(sinθ)^2 =cos^2θ +sin^2θ =1 = R.H.S. ...

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First Principle of Differentiation

cos 90 o -θ c...

Question

$\frac{cos (90^{o} - θ) cos θ}{tan θ} + {cos}^{2} (90^{o} - θ) = 1$

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