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Question

cosθsinθ+1cosθ+sinθ1=cosecθ+cotθ

A
True
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B
False
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Solution

The correct option is A True
Given

LHS

sinθcosθ+1sinθ+cosθ1

Dividing Numerator and Denominator by sinθ

cotθ+cosecθ1cotθcosecθ+1

cotθ+cosecθ(cosec2θcot2θ)cotθcosecθ+1

cotθ+cosecθ(cosecθcotθ)(cosecθ+cotθ)cotθcosecθ+1

cotθ+cosecθ(cosecθcotθ)(cosecθ+cotθ)cotθcosecθ+1

(cotθ+cosecθ)(cotθcosecθ+1)cotθcosecθ+1

cosecθ+cotθ

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