The correct option is D 17(2x 3)^2 ddx(3x+42x 3) =3(2x 3) 2(3x+4)(2x 3)^2 =6x 9 6x 8(2x 3)^2 #160; = 17(2x 3)^2 ...

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Ratio

ddx3x+42x-3

Question

$\frac{d}{d x} (\frac{3 x + 4}{2 x - 3})$

\frac{17}{(2 x - 3)^{2}}

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\frac{1}{(2 x - 3)^{2}}

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\frac{- 1}{(2 x - 3)^{2}}

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\frac{- 17}{(2 x - 3)^{2}}

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Solution

The correct option is D $\frac{- 17}{(2 x - 3)^{2}}$
$\frac{d}{d x} (\frac{3 x + 4}{2 x - 3})$

$= \frac{3 (2 x - 3) - 2 (3 x + 4)}{(2 x - 3)^{2}}$

$= \frac{6 x - 9 - 6 x - 8}{(2 x - 3)^{2}}$

$= \frac{- 17}{(2 x - 3)^{2}}$

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