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Question

ddx[tanxcotxtanx+cotx]=

A
2 sin2x
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B
-2 sin2x
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C
2 cos 2x
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D
-2cos 2x
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Solution

The correct option is A 2 sin2x
ddx⎜ ⎜ ⎜sinxcosxcosxsinxsinxcosx+cosxsinx⎟ ⎟ ⎟=ddx(sin2xcos2xsin2x+cos2x)
=ddx(sin2xcos2x)=2sinxcosx+2cosxsinx=2sin2x(A)

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