$\frac{d y}{d x} = (x^{3} + x^{2} + x + 1)$ . Find y

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Solution

$\frac{d y}{d x} = (x^{3} + x^{2} + x + 1) y = \int x^{3} + x^{2} + x + 1 d x y = \frac{x^{4}}{4} + \frac{x^{3}}{3} + \frac{x^{2}}{2} + x + c$

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