-a-b- -b-c- b-c- -c-a- c-a- -a-b- a-b- b-c- c-a- - is equal to

The correct option is C [a b c]^2(a×b) × (b×c)=((a×b).c)b ((a×b).b)c =[abc]b (b×c) × (c×a)=[abc]c (c×a) × (a×b)=[abc]a So, [ [a b c]b [a b c] ...

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Sequence

[a⃗×b⃗ ×b⃗×c⃗...

Question

$\frac{[(\to a \times \to b) \times (\to b \times \to c) (\to b \times \to c) \times (\to c \times \to a) (\to c \times \to a) \times (\to a \times \to b)]}{[\to a \times \to b \to b \times \to c \to c \times \to a]}$ is equal to

| \to a |^{2} | \to b |^{2} | \to c |^{2}

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{[\to a \to b \to c]}^{2}

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\frac{[\to a \times \to b \to b \times \to c \to c \times \to a]}{2}

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\frac{| \to a |^{2} | \to b |^{2} | \to c |^{2}}{2}

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Solution

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Similar questions

[\to a + \to b - \to c \to b + \to c - \to a \to c + \to a - \to b

\to a, \to b

\to c,

[(\to a + \to b) (\to b + \to c) (\to c + \to a)] = 2 [\to a \to b \to c] .

| \to a | = 3, ∣ ∣ \to b ∣ ∣ = 4, | \to c | = 5, \to a ⊥ (\to b + \to c), \to b ⊥ (\to c + \to a)

\to c ⊥ (\to a + \to b)

\sqrt{2} ∣ ∣ \to a + \to b + \to c ∣ ∣

\to a, \to b, \to c

\to a \times (\to b + \to c) + \to b \times (\to c + \to a) + \to c \times (\to a + \to b)

[\to a - \to b

\to b - \to c

\to c - \to a] + [\to a \times \to b

\to b \times \to c

\to c \times \to a]

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