Question

$\frac{{\sec }^2\theta {\csc }^2\theta }{{\sec }^2\theta -{\csc }^2\theta }=\frac{1}{{\sin }^2\theta -{\cos }^2\theta }$

• A. True
• B. False

Answer 1

The correct option is A True

$\frac{{\sec }^2\theta {\csc }^2\theta }{{\sec }^2\theta -{\csc }^2\theta }\frac{\frac{1}{{\cos }^2\theta {\sin }^2\theta }}{\frac{1}{{\cos }^2\theta }-\frac{1}{{\sin }^2\theta }}\frac{\frac{1}{{\cos }^2\theta {\sin }^2\theta }}{\frac{{\sin }^2\theta -{\cos }^2\theta }{{\cos }^2\theta {\sin }^2\theta }}\frac{1}{{\sin }^2\theta -{\cos }^2\theta }$