Sin8-cos- - sin6-cos3-cos2-cos- - sin3-sin4-

The correct option is D tan2α sin8αcosα sin6αcos3αcos2αcosα sin3αsin4α =2sin8αcosα 2sin6αcos3α2cos2αcosα 2sin3αsin 4α =sin9α+sin7α sin9 ...

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Sum of Trigonometric Ratios in Terms of Their Product

sin8αcosα - s...

Question

$\frac{sin 8 α cos α - sin 6 α cos 3 α}{cos 2 α cos α - sin 3 α sin 4 α} =$

cot 2 α

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tan 2 α

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cos 2 α

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sin 2 α

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Solution

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Similar questions

\frac{{tan}^{2} α - {sin}^{2} α}{{cot}^{2} α - {cos}^{2} α} = (tan α)^{K}

K \in N

K

c o s^{2} α - s i n^{2} α = t a n^{2} β .

t a n^{2} α = c o s^{2} β - s i n^{2} β .

{tan}^{2} α = {cos}^{2} β - {sin}^{2} β

{cos}^{2} α - {sin}^{2} α = {tan}^{2} β

{cos}^{2} θ - {sin}^{2} θ = {tan}^{2} α

{cos}^{2} α - {sin}^{2} α = {tan}^{2} θ

cos 2 α = {cos}^{2} α - {sin}^{2} α

sin 2 α = 2 sin α cos α

(x tan α + y cot α) (x cot α + y tan α) - 2 x y {cot}^{2} 2 α

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