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Byju's Answer
Standard XII
Mathematics
Trigonometric Ratios of Multiples of an Angle
sin Acos B+co...
Question
sin
A
cos
B
+
c
o
s
e
c
C
cot
B
+
tan
C
cos
2
B
sin
A
sin
C
=
[1 mark]
A
-1
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B
0
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C
1
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D
2
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Solution
The correct option is
B
0
cos
B
=
cos
90
°
=
0
and
cot
B
=
cot
90
°
=
0
sin
A
cos
B
+
c
o
s
e
c
C
cot
B
+
tan
C
cos
2
B
sin
A
sin
C
=
(
sin
A
)
(
0
)
+
(
c
o
s
e
c
B
)
(
0
)
+
(
tan
C
)
(
0
)
sin
A
sin
C
=
0
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0
Similar questions
Q.
sin
A
cos
B
+
c
o
s
e
c
C
cot
B
+
tan
C
cos
2
B
sin
A
sin
C
=
[1 mark]
Q.
In triangle ABC, right-angled at B, if tan A =
1
/
√
3
, then, cos Acos C - sinAsin C =
___
.
Q.
In
△
A
B
C
, right angled at
C
, if
tan
A
=
1
√
3
, find the value of:
cos
A
cos
C
−
sin
A
sin
C
Q.
If
tan
A
=
1
and
tan
B
=
√
3
,
then evaluate:
sin
A
cos
B
+
cos
A
sin
B
.
Q.
If
sin
A
cos
B
=
1
√
2
and
sin
B
cos
A
=
−
1
2
√
3
,
then
sin
(
A
−
B
)
=
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