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Question

sinAcosB+cosecCcotB+tanCcos2BsinAsinC=



[1 mark]

A
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B
0
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C
1
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D
2
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Solution

The correct option is B 0
cosB=cos90°=0 and cotB=cot90°=0

sinAcosB+cosecCcotB+tanCcos2BsinAsinC=(sinA)(0)+(cosecB)(0)+(tanC)(0)sinAsinC=0

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