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Integration of Trigonometric Functions

sinθ-cosθ+1si...

Question

$\frac{sin θ - cos θ + 1}{sin θ + cos θ - 1} = \frac{1}{sec - tan θ}$

True

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False

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Solution

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\frac{tan θ}{1 - tan θ} - \frac{cot θ}{1 - cot θ} = \frac{cos θ + sin θ}{cos θ - sin θ}

\frac{s i n Θ - c o s Θ + 1}{s i n Θ + c o s Θ - 1} = \frac{1}{s i n Θ - t a n Θ}

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