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Question

sinxa=cosxb, prove that a sin2x+bcos2x=b.

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Solution

asin2x+bcos2x=2asinxcosx+b(cos2xsin2x)

Since acosx=bsinx

above equation becomes 2sinx(bsinx)+b(cos2xsin2x)=b(cos2x+sin2x)=b

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