Question

$\frac{\sin {30}^0+\tan {45}^0+\text{cosec}{60}^0}{\sec {30}^0+\cos {60}^0+\cot {45}^0}=m,findm$

Answer 1

LHS ${\sin 30}^0=\frac{1}{2},\sec {30}^0=\frac{2}{\sqrt{3}}$

${\tan 45}^0=1,{\cos 45}^0=1$

${cosec60}^0=\frac{2}{\sqrt{3}},{\cos 60}^0=\frac{1}{2}$

Now putting values in given expression

$\frac{\frac{1}{2}+1+\frac{2}{\sqrt{3}}}{\frac{2}{\sqrt{3}}+\frac{1}{2}+1}=1=m$