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Byju's Answer
Standard XII
Mathematics
General Solution of Trigonometric Equation
tan 2250 . co...
Question
tan
225
0
.
cos
81
0
.
cot
69
0
cot
261
0
+
tan
21
0
=
__________
A
1
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B
1
√
2
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C
√
3
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D
1
√
3
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Solution
The correct option is
C
√
3
Given,
tan
225
0
−
cot
81
0
cot
69
0
cot
261
0
+
tan
21
0
=
tan
45
0
−
tan
9
0
tan
21
0
tan
9
0
+
tan
21
0
=
1
−
tan
9
0
tan
21
0
tan
9
0
+
tan
21
0
=
1
tan
(
9
0
+
21
0
)
=
1
tan
30
0
=
√
3
Suggest Corrections
0
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⋅
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2
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⋅
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+
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−
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2
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is equal to :
Q.
If
a
1
>
a
2
>
a
3
,
b
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>
b
2
>
b
3
and
a
i
b
j
≠
1
for
1
≤
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j
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, then the determinant
Δ
=
∣
∣ ∣ ∣ ∣ ∣ ∣
∣
1
−
a
3
1
b
3
1
1
−
a
1
b
1
1
−
a
3
1
b
3
2
1
−
a
1
b
2
1
−
a
3
1
b
3
3
1
−
a
1
b
3
1
−
a
3
2
b
3
1
1
−
a
2
b
1
1
−
a
3
2
b
3
2
1
−
a
2
b
2
1
−
a
3
2
b
3
3
1
−
a
2
b
3
1
−
a
3
3
b
3
1
1
−
a
1
b
1
1
−
a
3
3
b
3
2
1
−
a
3
b
2
1
−
a
3
3
b
3
3
1
−
a
3
b
3
∣
∣ ∣ ∣ ∣ ∣ ∣
∣
is
Q.
Find the value of
1
1
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2
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1
3
−
(
1
2
)
+
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