wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

tan3θ1tanθ1=sec2θ+tanθ

Open in App
Solution

Given,

tan3θ1tanθ1=sec2θ+tanθ

LHS:

=tan3θ1tanθ1

using a3b3 formula, we get,

=(tanθ1)(tan2θ+tanθ×1+1)tanθ1

=tan2θ+tanθ+1

=sec2θ+tanθ

:RHS


flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
General Solutions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon