The correct option is A 2√(3) tan 60 #176; #160; sin 30 #176; #160; =√(3)12 =√(3)×21 =2√(3) Hence, the answer is 2√(3) ...

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Integration as Antiderivative

tan60osin30o

Question

$\frac{t a n 60^{o}}{s i n 30^{o}}$

2 \sqrt{3}

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\sqrt{3}

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4 \sqrt{3}

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2

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Solution

The correct option is A $2 \sqrt{3}$
$\frac{tan 60 °}{sin 30 °}$

$= \frac{\sqrt{3}}{\frac{1}{2}}$
$= \sqrt{3} \times \frac{2}{1}$
$= 2 \sqrt{3}$
Hence, the answer is $2 \sqrt{3} .$

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Similar questions

\frac{sin 60^{o} + sin 30^{o}}{sin 60^{o} - sin 30^{o}} = \frac{tan 60^{o} + tan 45^{o}}{tan 60^{o} - tan 45^{o}}

x

x {sec}^{2} 45^{o} . c o s e c^{2} 45^{o} + 2 (sin 60^{o} + sin 30^{o}) = tan 60^{o}

\sqrt{5^{2} + 3^{2} + 4 \times 5 \times 3 \times sin 30^{o}}

\frac{cos 30^{o} + sin 60^{o}}{1 + cos 60^{o} + sin 30^{o}} = \frac{\sqrt{3}}{4}

\sqrt{3}

30^{o}

s i n 30^{o} = \frac{1}{2}

s i n 60^{o} = \frac{\sqrt{3}}{2}

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