$\frac{Real Depth}{Apparent Depth} =$

μ

(Refractive index)

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C =

speed of light

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i_{c} =

Critical angle

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All

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Solution

The correct option is A $μ$ (Refractive index)
$^{a i r} μ_{m e d i u m} = \frac{Real Depth}{Apparent Depth}$
Refractive index $= \frac{Real Depth}{Apparent Depth}$

Suggest Corrections

Similar questions

Refractive index=real depthapparent depth

Prove that

Refractive index = $\frac{r e a l d e p t h}{a p p a r e n t d e p t h}$

\frac{R e a l d e p t h}{A p p a r e n t d e p t h}

30^{0}

μ = 1.5

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