Question

$\frac{x}{10}+\frac{y}{5}-1=0$$\frac{x}{8}+\frac{y}{6}=15$
Solve By method elimination

Answer 1

$\frac{x}{10}+\frac{y}{5}=1$

$\frac{x}{60}+\frac{y}{30}=\frac{1}{6}$ (Multipying by $\frac{1}{6}$ on both hand.) $⟶\left(1\right)$

$\frac{x}{8}+\frac{y}{6}=15$

$\frac{x}{40}+\frac{y}{30}=\frac{15}{5}=3$ (Multipying by $\frac{1}{5}$ on both hand.) $⟶\left(2\right)$

Subtracting $\left(1\right)$ from $\left(2\right)$,

$\frac{x}{40}-\frac{x}{60}=3-\frac{1}{6}=\frac{17}{6}$

$\frac{20x}{40\times 60}=\frac{17}{6}$

$x=340$

So, $\frac{340}{10}+\frac{y}{5}=1⟹y=-165$