Y - 7 - 8y9y - 3 - 4y - 23

y (7 8y)9y (3+4y)=23 y 7+8y9y 3 4y=23 9y 75y 3=23 3(9y 7)=2(5y 3) 27y 21=10y 6 27y 10y= 6+21 17y=15 y=1517 ...

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Byju's Answer

Standard VI

Mathematics

Ratio

y - 7 - 8y9y ...

Question

$\frac{y - (7 - 8 y)}{9 y - (3 + 4 y)} = \frac{2}{3}$

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Solution

$\frac{y - (7 - 8 y)}{9 y - (3 + 4 y)} = \frac{2}{3}$
$\frac{y - 7 + 8 y}{9 y - 3 - 4 y} = \frac{2}{3}$
$\frac{9 y - 7}{5 y - 3} = \frac{2}{3}$
$3 (9 y - 7) = 2 (5 y - 3)$
$27 y - 21 = 10 y - 6$
$27 y - 10 y = - 6 + 21$
$17 y = 15$
$y = \frac{15}{17}$

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Similar questions

Solve the following equations and verify your answer :

$\frac{y - (7 - 8 y)}{9 y - (3 + 4 y)} = \frac{2}{3}$

Q. Find the value of

y

in the equation :

\frac{(2 - 3 y) + 4 y}{9 y - (8 y + 7)} = \frac{4}{5}

Q. Evaluate:

2 y^{4} + 7 y^{2} + 8 y^{3} + 4 y + 3 b y (y + 3)

Verify division algorithm i.e., Dividend = Divisor $\times$ Quotient + Remainder, in each of the following. Also, write the quotient and remainder :

$\begin{matrix} (i) & 14 x^{2} + 13 x - 15 & 7 x - 4 (i i) & 15 z^{2} - 20 z^{2} + 13 z - 12 & 3 z - 6 (i i i) & 6 y^{5} - 28 y^{3} + 3 y^{2} + 30 y - 9 & 2 y^{2} - 6 (i v) & 34 x - 22 x^{3} - 12 x^{4} - 10 x^{2} - 75 & 3 x + 7 (v) & 15 y^{4} - 16 y^{3} + 9 y^{2} - \frac{10}{3} y + 6 & 3 y - 2 (v i) & 4 y^{3} + 8 y + 8 y^{2} + 7 & 2 y^{2} - y + 1 (v i i) & 6 y^{5} + 4 y^{4} + 4 y^{3} + 7 y^{2} + 27 y + 6 & 2 y^{3} + 1 \end{matrix}$

Simplify :

7 x^{3} + 8 y^{3} - (4 x + 3 y) (16 x^{2} - 12 x y + 9 y^{2})

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y−(7−8y)9y−(3+4y)=23

y−(7−8y)9y−(3+4y)=23y−7+8y9y−3−4y=239y−75y−3=233(9y−7)=2(5y−3)27y−21=10y−627y−10y=−6+2117y=15y=1517

$\frac{y - (7 - 8 y)}{9 y - (3 + 4 y)} = \frac{2}{3}$

$\frac{y - (7 - 8 y)}{9 y - (3 + 4 y)} = \frac{2}{3}$
$\frac{y - 7 + 8 y}{9 y - 3 - 4 y} = \frac{2}{3}$
$\frac{9 y - 7}{5 y - 3} = \frac{2}{3}$
$3 (9 y - 7) = 2 (5 y - 3)$
$27 y - 21 = 10 y - 6$
$27 y - 10 y = - 6 + 21$
$17 y = 15$
$y = \frac{15}{17}$