Question

Diagonals AC and BD of a square ABCD intersect at P. What is $\angle$CPB = _______.

• A. 90∘
• B. ${90}^{\circ }$
• C. ${360}^{\circ }$
• D. ${180}^{\circ }$

Answer 1

The correct option is B

${90}^{\circ }$

In a square, diagonals bisect each other right angles. Hence $\angle$CPB = 90°