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Question

Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. Prove that ar(ΔAOD) = ar(ΔBOC).

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Solution



Given: In trapezium ABCD, ABDC.To prove: arAOD=arBOCProof:Since, ADC and BCD are on the same base DC and between same parallel lines AB and DC.So, arADC=arBDCarADC-arDOC=arBDC-arDOC arAOD=arBOC

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