Given: Diagonals of a quadrilateral ABCD bisect each other
Since, the diagonals of a quadrilateral ABCD bisect each other
Therefore, It is a parallelogram
Sum of interior angles of a parallelogram is 180°
⇒ ∠A + ∠B = 180°
⇒ 35° + ∠B = 180°
⇒ ∠B = 180° − 35°
⇒ ∠B = 145°
Hence, ∠B = 145°.