Question

Diagonals of a quadrilateral ABCD bisect each other. If $\angle A={35}^{\circ }$, determine $\angle B.$

Answer 1

Since diagonals of a quadrilateral bisect each other, so it is a parallelogram.

Therefore, the sum of interior angles between two parallel lines is ${180}^{\circ }$ I.e

$\angle A+\angle B={180}^{\circ }\Rightarrow \angle B={180}^{\circ }-\angle A={180}^{\circ }-{35}^{\circ }[\angle A=35,given]\Rightarrow \angle B={145}^{\circ }$