The correct option is A 90°
Let ABCD is a rhombus.
⇒AB=BC=CD=DA [ Adjacent sides are equal in rhombus ]
In ΔAOD and ΔCOD
⇒OA=OC [ Diagonals of rhombus bisect each other ]
⇒OD=OD [ Common side ]
⇒AD=CD
∴ΔAOD≅ΔCOD [ By SSS congruence rule ]
⇒∠AOD=∠COD [ CPCT ]
⇒∠AOD+∠COD=180° [ Linear pair ]
⇒2∠AOD=180°
∴∠AOD=90°
Hence, the diagonals of a rhombus bisect each other at right angles.