Question

Diagram shows three capacitors with capacitance and breakdown voltage mentioned. What should be maximum value of the external emf of source such that no capacitor breaks down?

• A. 1 V
• B. 2 V
• C. 1.5 V
• D. 4 V

Answer 1

The correct option is C 1.5 V

We know that

$q=cv$

Total charge of two parallel circuit is ,

$q_T=CV+2CV{q}_T=3CV$

Maximum charge stored by 6C capacitor

$q=6C\times V=6CV$

Hence q < q${}_T$ So Maximum charge flow through the battery $3CV$

And

$C_{eq}=\frac{3\times 6}{3+6}=2C$

$Sourcevoltage=\frac{3C}{2C}=1.5V$

CORRECT OPTION IS C