Diameter and slant height of a cone are $14 m$ and $25 m$ respectively. Find it total surface area.

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Solution

Given, the base diameter of cone $= 14 m$
$∴$ Radius $(r) = \frac{14}{5} = 7 m$
Slant height $(d) = 25 m$
Total surface area of the cone $= π r (1 + r)$

$= \frac{22}{7} \times 7 \times (25 + 7)$

$= \frac{22}{7} \times 7 \times 32$

$= 22 \times 32$
$= 744 m^{2}$
Hence, total surface area of cone $704 m^{2}$

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Diameter and slant height of a cone are 14 m and 25 m respectively. Find it total surface area.

Given, the base diameter of cone =14 m∴ Radius (r)=145=7 mSlant height (d)=25 mTotal surface area of the cone =πr(1+r) =227×7×(25+7) =227×7×32 =22×32 =744 m2Hence, total surface area of cone 704 m2

Diameter and slant height of a cone are $14 m$ and $25 m$ respectively. Find it total surface area.