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Question

Diameter of a wire measured by a screw guage in four different readings is found to be 2.20 mm, 2.10 mm, 2.40 mm and 1.90 mm.

A

Number of significant figures in all readings is two.

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B
Error in 1st reading is negative.
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C
Mean error of readings is zero.
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D
Error in 4th reading is 0.25 mm.
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Solution

The correct options are
B Error in 1st reading is negative.
D Error in 4th reading is 0.25 mm.
True diameter is, D=D1+D2+D3+D44=2.2+2.1+2.4+1.94
D =2.15 mm
ΔD1=DD1=2.152.20=0.05
ΔD4=DD4=2.151.90=0.25
ΔDmean=|ΔD1|+|ΔD2|+|ΔD3|+|ΔD4|4=0.15
Number of significant figures is 3 in each of the cases.

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