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Screw Gauge

Diameter of a...

Question

Diameter of a wire, using screw gauge is

P S R - H S R + L C

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P S R + H S R \times L C

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P S R - H S R - L C

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P S R \times H S R \times L C

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Solution

The correct option is A $P S R + H S R \times L C$
That's elementary, how ralue is read from screw gauge:
Meascored quantity = (Main scale reading $+$ Circular scale ) $\times$ Leat count
= PSR + HSR $\times L C$
hence option B is correct

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