Question

Diameter of the beach ball is $42cm$. Find the surface area and volume.

Answer 1

$\begin{array}{c}Surfacearea,volumeofbeachballare4\pi r^{2}andd\left(\frac{4}{3}\right)\pi r^3\\ respectivelybeachball\\ \left[\because readius=\frac{d}{2}\right]\\ \Rightarrow Surfacearea=4\pi r^2=4\pi \times \frac{d^2}{4}=\pi \times 42\times 42=\frac{22}{7}\times 42\times 42=5544c{m}^2\\ \Rightarrow Volumeofabeachball=\frac{4}{3}\times \frac{22}{7}\times \frac{D^3}{8}=\frac{4}{3}\times \frac{22}{7}\times \frac{42\times 42\times 42}{8}\\ =388.8c{m}^2\end{array}$