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Byju's Answer

Standard XII

Mathematics

Property 2

Diameter of t...

Question

Diameter of the escribed circle of $△ A B C$ is equal to perimeter of the triangle. Then $△ A B C$ is

Acute angled

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Right Angled

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Equilateral

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Isosceles

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Solution

The correct option is B Right Angled
$2 r_{1} = 2 s ⟹ r_{1} = s$

$⟹ s tan \frac{A}{2} = s ⟹ \frac{A}{2} = 45^{\circ} ⟹ A = 90^{\circ}$

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Diameter of the escribed circle of △ABC is equal to perimeter of the triangle. Then △ABC is

The correct option is B Right Angled2r1=2s⟹r1=s ⟹stanA2=s⟹A2=45∘⟹A=90∘

Diameter of the escribed circle of $△ A B C$ is equal to perimeter of the triangle. Then $△ A B C$ is

The correct option is B Right Angled
$2 r_{1} = 2 s ⟹ r_{1} = s$

$⟹ s tan \frac{A}{2} = s ⟹ \frac{A}{2} = 45^{\circ} ⟹ A = 90^{\circ}$