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Standard XII

Physics

Limit of Resolution

Diameter of t...

Question

Diameter of the objective of a telescope is 200 cm. What is the resolving power of a telescope? Take wavelength of light = 5000 $˚ A$ .

6.56 \times 10^{6}

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3.28 \times 10^{5}

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1 \times 10^{6}

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3.28 \times 10^{6}

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Solution

The correct option is D $3.28 \times 10^{6}$
Given : $D = 200$ cm $= 2$ m $λ = 5000$ $o A = 5 \times 10^{- 7}$ m
Resolving power of telescope $R P = \frac{D}{1.22 λ}$
$∴$ $R P = \frac{2}{1.22 \times 5 \times 10^{- 7}} = 3.28 \times 10^{6}$

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Diameter of the objective of a telescope is 200 cm. What is the resolving power of a telescope? Take wavelength of light = 5000 ˚A.

The correct option is D 3.28×106Given : D=200 cm =2 m λ=5000 oA=5×10−7 mResolving power of telescope RP=D1.22λ∴ RP=21.22×5×10−7=3.28×106

Diameter of the objective of a telescope is 200 cm. What is the resolving power of a telescope? Take wavelength of light = 5000 $˚ A$ .

The correct option is D $3.28 \times 10^{6}$
Given : $D = 200$ cm $= 2$ m $λ = 5000$ $o A = 5 \times 10^{- 7}$ m
Resolving power of telescope $R P = \frac{D}{1.22 λ}$
$∴$ $R P = \frac{2}{1.22 \times 5 \times 10^{- 7}} = 3.28 \times 10^{6}$