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Diborane

Diborane B2...

Question

Diborane $(B_{2} H_{6})$ on combustion give

Boron

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Hydrogen

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B_{2} O_{3}

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H_{2} B_{4} O_{7}

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Solution

The correct option is C $B_{2} O_{3}$
The combustion of diborane give $B_{2} O_{3}$
according to the reaction
$B_{2} H_{6} (g) + 3 O_{2} (g) \to B_{2} O_{3} (s) + 3 H_{2} O () g$ .

Suggest Corrections

Similar questions

H_{3} B O_{3}

△ - \to

A + B . A & B

B_{2} H_{6}

O_{2}

H_{2} O

B_{2} H_{6} (g) + 3 O_{2} (g) \to B_{2} O_{3} (s) + 3 H_{2} O (g)

B_{2} H_{6 (g)} + 3 O_{2 (g)} \to B_{2} O_{3 (s)} + 3 H_{2} O (g)

2 B (s) + (3 / 2) O_{2 (g)} \to B_{2} O_{3 (s)}

Δ H = - 1273 k J m o l^{- 1}

H_{2 (g)} + (1 / 2) O_{2 (g)} \to H_{2} O (1)

Δ H = - 286 k J m o l^{- 1}

H_{2} O_{(} 1) \to H_{2} O_{(} g)

Δ H = 44 k J m o l^{- 1}

2 B (s) + 3 H_{2 (g)} \to B_{2} H_{6 (g)}

Δ H = 36 K J m o l^{- 1}

B_{2} H_{6}

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