You visited us 1 times! Enjoying our articles? Unlock Full Access!

Kolbe Electrolysis for Alkenes

Diborane does...

Question

Diborane does not react with:

C l_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

B r_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

I_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

F_{2}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $I_{2}$
Diborane react with halogens under controlled conditions.
$B_{2} H_{6} + C l_{2} \to B_{2} H_{5} C l + H C l$
$B_{2} H_{6} + C l_{2} \to 3 B C l_{3} + 3 H_{2}$
Diborane with chlorine and bromine reacts violently and gives controlled yield.
However, with iodine, it does not react at all.

Suggest Corrections

Similar questions

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

F_{2} > C l_{2} > B r_{2} > I_{2} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

H O C l > H C l O_{2} > H C l O_{3} > H C l O_{4} :

(x^{2} + y^{2})

x

y

F_{2} > C l_{2} > B r_{2} > I_{2}

F_{2} > C l_{2} > B r_{2} > I_{2}

C l > F > B r > I

F > C l > B r > I

I_{2}, {B r}_{2}, {C l}_{2}, F_{2}

I_{2} < {B r}_{2} < {C l}_{2} < F_{2}

F_{2} > C l_{2} > B r_{2} > I_{2}

F_{2} > C l_{2} > B r_{2} > I_{2}

C l > F > B r > I

F > C l > B r > I

B r_{2}

N a F, N a C l & N a I

Join BYJU'S Learning Program