Question

Diborane is a Lewis acid forming addition compound $B_2{H}_6.2N{H}_3$ with $N{H}_3$ a lewis base. It:

• A. Is ionic and exists as $\left[B{H}_2\right(N{H}_3{)}_2{]}^{+}$ and $[B{H}_4{]}^{-}$
• B. On heating, is converted into borazine, $B_3{N}_3{H}_6$
• C. Both (a) and (b)
• D. None of these

Answer 1

The correct option is C Both (a) and (b)

At low temperature, an addition product $B_2{H}_6.2N{H}_3$ exists as $\left[B{H}_2\right(N{H}_3{)}_2{]}^{+}$ and $[B{H}_4{]}^{-}$

$3B_2{H}_6.2N{H}_3\stackrel{200{}^{\circ }C}{\to }\underset{\text{Borazene}}{2B_3{N}_3{H}_6}+12H_2\uparrow$