Question

Diborane is a Lewis acid forming addition compound $B_2{H}_6\cdot 2N{H}_3$ with $N{H}_3,$ a Lewis base. This -

• A. Is ionic and exists as $\left[B{H}_2\right(N{H}_3{)}_2{]}^{+}$ and $[B{H}_4{]}^{-}$ ions
• B. On heating, is converted into borazine, $B_3{N}_3{H}_6$ (called inorganic benzene)
• C. Both are correct
• D. None is correct

Answer 1

The correct option is C Both are correct


(a) Diborane is a lewis acid it forms an addition product $B_2{H}_6.2N{H}_3$ on reaction with $N{H}_3$ which is ionic and it exsists as: $\left[B{H}_2\right(N{H}_3{)}_2{]}^{+}$ and $[B{H}_4{]}^{-}$ ions.

(b) On heating, it gets converted into Borazine which is also known as inorganic benzene.
$B_2{H}_6.2N{H}_3\stackrel{{200}^{o}C}{\to }2B_3{N}_3{H}_6+12H_2$

Therefore, the correct option is (c).