Diborane reacts $H C l$ in the presence of $A l {C l}_{3}$ and liberates :

H_{2}

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{C l}_{2}

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{B C l}_{3}

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{C l}_{2} a n d {B C l}_{3}

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Solution

The correct option is A $H_{2}$
Diborane reacts HCl in the presence of $A l C l_{3}$ and liberates hydrogen :

$B_{2} H_{6} + 6 H C l \to 2 B C l_{3} + 6 H_{2}$

Hence the correct option is A.

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