Dichromate ion in acidic medium oxidizes stannous ion as:
$x S n^{2 +} + y C r_{2} O_{7}^{2 -} + z H^{+} \to a S n^{4 +} + b C r^{3 +} + c H_{2} O$

the value of

x : y = 1 : 3

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the value of

x + y + z = 18

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a : b = 3 : 2

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the value of

z - c = 7

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Solution

The correct options are
B the value of $x + y + z = 18$
C the value of $z - c = 7$
D $a : b = 3 : 2$
The balanced reaction is as follows:
$3 S n^{2 +} + 14 H^{+} + C r_{2} O_{7}^{2 -} \to 3 S n^{3 +} + 2 C r^{3 +} + 7 H_{2} O$
So, the value of $x + y + z = 18$ .

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Similar questions

Dichromate ion in acidic medium oxidizes stannous ion as

$x - - S n^{2 +} + y - C r_{2} O_{7}^{2 -} + z - H^{+} \to a - - S n^{4 +} + b - C r^{3 +} + c - H_{2} O$ then

x S n^{2 +} + y C r_{2} O_{7}^{2 -} + z H^{+} \to a S n^{4 +} + b C r^{3 +} + c H_{2} O

x S n^{2 +} + y C r_{2} O_{7}^{2 -} + z H^{+} \to a S n^{4 +} + b C r^{3 +} + c H_{2} O

x S n^{2 +} + y C r_{2} O_{7}^{2 -} + z H^{+} ⟶ a S n^{4 +} + b C r^{3 +} + c H_{2} O

294 g

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