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Electronic Configuration

Dichromate io...

Question

Dichromate ion is treated with base, the oxidation number of $C r$ in the product formed is

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Solution

$C r_{2} O_{7}^{2 -} + 2 O H^{-} ⇌ 2 C r O_{4}^{2 -} + H_{2} O$

For $C r O_{4}^{2 -}$

$x + (- 2 \times 4) = - 2$

x = 6

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