Question

Die A has 4 red and 2 white faces where as die B has two red and 4 white faces. A fair coin is tossed. If head turns up, the game continues by throwing die A, if tail turns up then die B is to be used. Probability of getting a red face at any throw is

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Solution

The correct option is **A** 12

We can get a red face if (i) Head and Red from A or (ii) Tail and Red from B

Probability of getting a red face = 12∗46+12∗26=612=12

We can get a red face if (i) Head and Red from A or (ii) Tail and Red from B

Probability of getting a red face = 12∗46+12∗26=612=12

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